bash ограничение времени работы скрипта

#! /usr/local/bin/bash
###########################################
# Default values
#------------------------------------------

declare -i timeout=20    # default timeout in seconds.

Kill='/bin/kill'
split_line='-------------------------------------------------------------------------------'

success_msg='status OK'  # that what external program should return on success
#
###########################################
ftmp="$(mktemp /tmp/$(basename $0).XXXXXXXX)"
trap "rm -f ${ftmp}" 0 1 2 5 15

ext_prg=$1

( ${ext_prg} )>${ftmp} 2>&1 &   # run some program in subshell
cPID=$!                         # get PID of subshell
sleep 5                         # wait at least 5 seconds to get time for process to start
((timeout-=5))

status=0
if [[ ${timeout} -gt 0 ]]; then
    while [[ $( ps | grep -o -G "^${cPID}"; ) -eq ${cPID} && ${status} -eq 0 ]]; do
        status=$((timeout-- ? 0 : 1)); sleep 1
    done
fi

if [[ ${status} -eq 1 ]]; then
    eval '${Kill} -9 ${cPID}' &>/dev/null;  # If timeout occured - kill child process
    echo "${split_line}"
    echo `basename $0`": Err: Timeout occured."
    echo "Process(${cPID}): ${ext_prg}"
    echo "was killed because of timeout."
    echo "${split_line}"
    exit 1
else
    echo "${split_line}"
    echo -en "Process(${cPID}): ${ext_prg}\nterminate by itself successfully.\n"
    rc=$(cat ${ftmp} | awk "/${success_msg}/"'{print $2}')
    if [[ -z "${rc}" ]]; then
        echo "${ext_prg}: ERR: no success code returned!!!"
        exit 1
    else
        echo "${ext_prg}: return success code!!!"
    fi
    echo "${split_line}"
fi

exit 0

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